Em tham khảo nha :
\(\begin{array}{l}
16)\\
A\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
17)\\
Cl + 1e \to C{l^ - }\\
C\\
18)\\
B\\
NaOH + C{l_2} \to NaClO + NaCl + {H_2}O\\
19)\\
D\\
Hg + S \to HgS\\
20)\\
A\\
{n_{S{O_2}}} = \dfrac{{1,12}}{{22,4}} = 0,05mol\\
{n_{NaOH}} = 0,05 \times 1 = 0,05mol\\
T = \dfrac{{{n_{NaOH}}}}{{{n_{S{O_2}}}}} = \dfrac{{0,05}}{{0,05}} = 1\\
T = 1 \Rightarrow\text{Phản ứng tạo ra 1 muối :} NaHS{O_3}
\end{array}\)
