Đáp án:
\(\begin{array}{l}
b,\\
\% {V_{{C_2}{H_4}}} = 60\% \\
\% {V_{C{H_4}}} = 40\% \\
c,{V_{C{O_2}}} = 17,92l
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a,{C_2}{H_4} + B{r_2} \to {C_2}{H_4}B{r_2}\\
b,\\
{m_{B{r_2}}} = 8,4g \to {m_{{C_2}{H_4}}} = 8,4g\\
\to {n_{{C_2}{H_4}}} = 0,3mol\\
\to {V_{{C_2}{H_4}}} = 6,72l\\
\to \% {V_{{C_2}{H_4}}} = \dfrac{{6,72}}{{11,2}} \times 100\% = 60\% \\
\to \% {V_{C{H_4}}} = 100\% - 60\% = 40\%
\end{array}\)
\(\begin{array}{l}
c,\\
C{H_4} + 2{O_2} \to C{O_2} + 2{H_2}O\\
{C_2}{H_4} + 3{O_2} \to 2C{O_2} + 2{H_2}O\\
{n_{C{O_2}}} = {n_{C{H_4}}} + 2{n_{{C_2}{H_4}}} = 0,8mol\\
\to {V_{C{O_2}}} = 17,92l
\end{array}\)
