Đáp án:
Bạn tham khảo lời giải ở dưới nhé !
Giải thích các bước giải:
\(\begin{array}{l}
3.\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
{n_{Zn}} = 0,2mol\\
a)\\
{n_{{H_2}}} = {n_{Zn}} = 0,2mol\\
\to {V_{{H_2}}} = 4,48l\\
b)\\
{n_{HCl}} = 2{n_{Zn}} = 0,4mol\\
\to {m_{HCl}} = 14,6g\\
\to C{\% _{HCl}} = \dfrac{{14,6}}{{200}} \times 100\% = 7,3\% \\
c)\\
2{H_2} + {O_2} \to 2{H_2}O\\
{n_{{O_2}}} = \dfrac{1}{2}{n_{{H_2}}} = 0,1mol\\
\to {V_{{O_2}}} = 2,24l
\end{array}\)
\(\begin{array}{l}
4.\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
{n_{Zn}} = 0,1mol\\
a)\\
{n_{{H_2}}} = {n_{Zn}} = 0,1mol\\
\to {V_{{H_2}}} = 2,24l\\
b)\\
{n_{HCl}} = 2{n_{Zn}} = 0,2mol\\
\to {m_{HCl}} = 7,3g\\
\to C{\% _{HCl}} = \dfrac{{7,3}}{{100}} \times 100\% = 7,3\% \\
c)\\
2{H_2} + {O_2} \to 2{H_2}O\\
{n_{{O_2}}} = \dfrac{1}{2}{n_{{H_2}}} = 0,05mol\\
\to {V_{{O_2}}} = 1,12l
\end{array}\)
