Đáp án:
\({V_{{H_2}}} = 1,7l\)
Giải thích các bước giải:
\(\begin{array}{l}
{V_{{C_2}{H_5}OH}} = 25 \times \dfrac{{35}}{{100}} = 8,75\,ml\\
{m_{{C_2}{H_5}OH}} = 8,75 \times 0,8 = 7g\\
{n_{{C_2}{H_5}OH}} = \dfrac{7}{{46}}\,mol\\
2{C_2}{H_5}OH + 2Na \to 2{C_2}{H_5}ONa + {H_2}\\
{n_{{H_2}}} = \dfrac{7}{{46}} \times \dfrac{1}{2} = \dfrac{7}{{92}}\,mol\\
{V_{{H_2}}} = \dfrac{7}{{92}} \times 22,4 \approx 1,7l
\end{array}\)
