`PTHH: Mg+2CH_3COOH→(CH_3COO)_2Mg+H_2↑`
a,Ta có: `n_(Mg)=m/M=(2,4)/24=0,1(mol)`
Theo `PTHH`,ta thấy: `n_(Mg)=n_(H_2)=0,1(mol)`
`⇒V_(H_2)=n.22,4=0,1.22,4=2,24(l)`
b,Theo `PTHH`,ta thấy: `n_(CH_3COOH)=2n_(H_2)=2.0,1=0,2(mol)`
`⇒m_(ctCH_3COOH)=n.M=0,2.(12+3+12+16.2+1)=12(g)`
`⇒ C% CH_3COOH=(100.m_(ct))/m_(dd)=100.12/200=6%`
Xin hay nhất =_=