$\frac{1}{4}$ + $\frac{1}{3}$ : |2x-1|=$\frac{11}{12}$
$\frac{1}{3}$ : |2x-1| = $\frac{11}{12}$ - $\frac{1}{4}$
$\frac{1}{3}$ : |2x-1| = $\frac{2}{3}$
|2x-1| = $\frac{1}{3}$ : $\frac{2}{3}$
|2x-1| = $\frac{1}{2}$
⇒\(\left[ \begin{array}{l}2x-1=\frac{1}{2} \\2x-1 = \frac{-1}{2} \end{array} \right.\)
⇒\(\left[ \begin{array}{l}2x = \frac{3}{2} \\2x = \frac{1}{2} \end{array} \right.\)
⇒\(\left[ \begin{array}{l}x= \frac{3}{4} \\x = \frac{1}{4} \end{array} \right.\)
vậy \(\left[ \begin{array}{l}x= \frac{3}{4} \\x=\frac{1}{4} \end{array} \right.\)
