a)
Ta có:
\({V_{dd}} = 400{\text{ ml = 0}}{\text{,4 lít}}\)
\( \to {C_{M{\text{ N}}{{\text{a}}_2}C{O_3}}} = \frac{{0,5}}{{0,4}} = 1,25M\)
b)
Ta có:
\({m_{Zn{{(N{O_3})}_2}}} = {m_{dd}}.C\% = 250.15\% = 37,5{\text{ gam}}\)
\( \to {n_{Zn{{(N{O_3})}_2}}} = \frac{{37,5}}{{65 + 62.2}} = 0,1984\text{ mol} \)
c)
200 gam dung dịch \(NaOH\) 10% chứa
\({m_{NaOH}} = 200.10\% = 20{\text{ gam}}\)
350 gam dung dịch \(NaOH\) 30% chứa
\({m_{NaOH}} = 350.30\% = 10,5{\text{ gam}}\)
Sau khi hòa 2 dung dịch
\({m_{dd}} = 200 + 350 = 550{\text{ gam}}\)
\({m_{NaOH}} = 20 + 10,5 = 30,5{\text{ gam}}\)
\( \to C{\% _{NaOH}} = \frac{{30,5}}{{550}} = 5,55\% \)