Đáp án:
2 ³ +4x ²-x-30 ≥0
ta có: 2x³ +4x ²-x-30= 2x³- 4x² +8x²-16x + 15x+30
= 2x² (x-2) + 8x(x-2) +15(x-2)
= (x-2) (2x²+8x+15)
=(x-2) [ 2(x²+4x+4) +7)]
= (x-2) [2(x+2)² +7]
2 x³ +4x ²-x-30 ≥ 0
⇔(x-2) [2(x+2)² +7] ≥ 0
⇔x-2≥0 ( do 2(x+2)² +7> 0 với mọi x)
⇔x ≥ 2