Đáp án:
\(\left\{ \begin{array}{l}
x = 1\\
y = 6
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
\left\{ \begin{array}{l}
\left( {{x^2} - 2x} \right) + 3y = 5\\
2\left( {{x^2} - 2x} \right) - 3y = - 8
\end{array} \right.\\
\to \left\{ \begin{array}{l}
3\left( {{x^2} - 2x} \right) = - 3\\
y = 5 - {x^2} + 2x
\end{array} \right.\\
\to \left\{ \begin{array}{l}
{x^2} - 2x + 1 = 0\\
y = 5 - {x^2} + 2x
\end{array} \right.\\
\to \left\{ \begin{array}{l}
{\left( {x - 1} \right)^2} = 0\\
y = 5 - {x^2} + 2x
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x = 1\\
y = 6
\end{array} \right.
\end{array}\)
