a) `(x-5)^2 = (1-3x)^2`
+) `x-5 = 1-3x`
`=> x + 3x =1+5`
`=> 4x= 6`
`=> x= 3/2`
+) `x -5 = 3x-1`
`=> x- 3x =-1+5`
`=> -2x = 4`
`=> x= = 4:(-2)`
`=> x= -2`
Vậy `x= -2` hoặc `x= 3/2`
b) `(3y-1)^10 = (3y-1)^20`
`=> (3y-1)^10 - (3y-1)^20 =0`
`=> (3y-1)^10 [1 - ( 3y-1)^2 ] =0`
`=>` \(\left[ \begin{array}{l}3y-1 =0\\1-(3y-1)^2=0\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}y=\frac{1}{3}\\(3y-1)^2=1\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}y=\frac{1}{3}\\3y-1=1\\3y-1=-1\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}y=\frac{1}{3}\\y=\frac{2}{3}\\y=0\end{array} \right.\)
Vậy `y = 1/3` hoặc `y= 2/3` hoặc `y=0`
