Trừ `(a+b+c)^2` cho `3(a^2+b^2+c^2)`
Ta có:
`(a+b+c)^2-3(a^2+b^2+c^2)`
`=a^2+b^2+c^2+2ab+2bc+2ac-3a^2-3b^2-3c^2`
`=-2a^2-2b^2-2c^2+2ab+2bc+2ac`
`=-(2a^2+2b^2+2c^2-2ab-2bc-2ac)`
`=-(a^2+a^2+b^2+b^2+c^2+c^2-2ab-2bc-2ac)`
`=-[(a^2-2ab+b^2)+(b^2-2bc+c^2)+(a^2-2ac+c^2)]`
`=-[(a-b)^2+(b-c)^2+(c-a)^2]` (hình như ra rồi đó ak)