`a) \ \ 2 sqrt(x+5)-1=5 \ \ (ĐK : x >= -5)`
`<=> 2 sqrt(x+5)=6`
`<=> sqrt(x+5)=3`
`<=> x+5=9`
`<=> x=4 \ \ (tm)`
Vậy `S={4}`
`b) \ \ (x+1)/x-2/(x+1)=1 \ \ (ĐK : x ne 0;-1)`
`<=> ((x+1)^2-2x)/(x(x+1))=(x(x+1))/(x(x+1))`
`=> x^2+2x+1-2x=x^2+x`
`<=> x^2-x^2+2x-2x-x=-1`
`<=> -x=-1`
`<=> x=1 \ \ (tm)`
Vậy `S={1}`