`3n vdots 5-2n`
`=>6n vdots 5-2n`
`=>3(2n-5)+15 vdots 5-2n`
Vì `3(2n-5) vdots 5-2n`
`=>15 vdots 5-2n`
`=>5-2n in Ư(15)={+-1,+-3,+-5,+-15}`
`=>2n in {4,6,2,8,0,10,20,-10}`
`=>n in {2,3,1,4,0,5,-5,10}`
Thử lại ta thấy `n in {0,1,2,4,10,3,5,-5}` thỏa mãn.