Đáp án:
`1)2x^2+3(x-1)(x+1)=5x(x+1)`
`<=>2x^2+3(x^2-1)=5x^2+5x`
`<=>2x^2+3x^2-3=5x^2+5x`
`<=>5x^2-3=5x^2+5x`
`<=>5x=-3`
`<=>x=-3/5`
Vậy `S={-3/5}`.
`2)(3x+2)(x-1)-3(x+1)(x-2)=4`
`3x^2-3x+2x-2-3(x^2-2x+x-2)=4`
`<=>3x^2-x-2-3(x^2-x-2)=4`
`<=>3x^2-x-2-3x^2+3x+6=4`
`<=>2x+4=4`
`<=>2x=0`
`<=>x=0`.
Vậy `S={0}`.
`3)(n-1)(n+4)-(n-4)(n+1)`
`=n^2+4n-n-4-(n^2+n-4n-4)`
`=n^2+3n-4-(n^2-3n-4)`
`=n^2+3n-4-n^2+3n+4`
`=6n vdots 6AAn in ZZ`.