Bài 1:
`1/2021+2012×2010/2011-2012`
`=1/2021+2012×(2010/2011-1)`
`=1/2021+2012×(-1/2011)=1/2021-2012/2011`
Bài 2:
Ta có: `|x-3/4|≥0`
`⇒M=|x-3/4|+2020/2021≥2020/2021`
Dấu `"="` xảy ra khi `x-3/4=0` `⇒x=3/4`
Vậy $Min_{M}=\dfrac{2020}{2021}$ khi `x=3/4`.