$\begin{array}{l}h)\ \text{Ta có : $\dfrac{127}{39}=\dfrac{117+10}{39}=3+\dfrac{10}{39}\\\dfrac{26}{8}=\dfrac{13}4=\dfrac{12+1}4=3+\dfrac14$}\\\text{- Ta lại có : $\dfrac{10}{39}>\dfrac{10}{40}=\dfrac14$}\\\to 3+\dfrac{10}{39}>3+\dfrac14\\\to\dfrac{127}{39}>\dfrac{26}8\\\,\\i)\ \text{Ta có : $\dfrac{2323}{2424}=\dfrac{23.101}{24.101}=\dfrac{23}{24}\\\dfrac{20212021}{20222022}=\dfrac{2021.10001}{2022.10001}=\dfrac{2021}{2022}$}\\\text{- Ta lại có :}\\\dfrac{23}{24}=\dfrac{24-1}{24}=1-\dfrac1{24}\\\dfrac{2021}{2022}=\dfrac{2022-1}{2022}=1-\dfrac1{2022}\\\text{- Vì 24 < 2022}\\\to\dfrac1{24}>\dfrac1{2022}\\\to 1-\dfrac1{24}<1-\dfrac1{2022}\\\to\dfrac{23}{24}<\dfrac{2021}{2022}\\\to\dfrac{2323}{2424}<\dfrac{20212021}{20222022}\\\,\\k)\ \text{Ta có : $\dfrac{-1111}{1212}=\dfrac{-11.101}{12.101}=\dfrac{-11}{12}\\\dfrac{141414}{-151515}=\dfrac{-10101.(-14)}{-10101.15}=\dfrac{-14}{15}$}\\\text{- Ta có :}\\\dfrac{-11}{12}=\dfrac{-12+1}{12}=-1+\dfrac1{12}\\\dfrac{-14}{15}=\dfrac{-15+1}{15}=-1+\dfrac1{15}\\\text{- Vì 12 < 15}\\\to\dfrac1{12}>\dfrac1{15}\\\to -1+\dfrac1{12}>-1+\dfrac1{15}\\\to\dfrac{-11}{12}>\dfrac{-14}{15}\\\to\dfrac{-1111}{1212}>\dfrac{141414}{-151515} \end{array}$
