`- 1 + | x - 5/6 | = 1/2`
`⇔ | x - 5/6 | = 1/2 - ( - 1 )`
`⇔ | x - 5/6 | = 3/2`
`⇔` \(\left[ \begin{array}{l}x - \frac{5}{6} = \frac{3}{2} \\x - \frac{5}{6} = \frac{- 3}{2}\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x = \frac{7}{3}\\x = \frac{- 2}{3}\end{array} \right.\)
Vậy , `x ∈ { 7/3 ; ( - 2 )/3 } .`