`C_6H_12O_6→2C_2H_5OH+2CO_2`
`V_(C_2H_5OH)=(1.40)/100=0,4l`
`4l=400ml`
`m_(C_2H_5OH)=400.0,8=320g`
`n_(C_2H_5OH)=(320)/46=(160)/(23)mol`
`→n_(C_6H_12O_6)=(80)/(23)mol`
`Vì` `H%=80%`
`→n_(C_6H_12O_6) bđ=(80)/(23).(100)/80=(100)/(23)mol`
`m_(C_6H_12O_6) bđ=(100)/(23).180≈782,61g`