Đáp án:
`(x+3)/327 + (x+3)/326 + (x+4)/325 + (x+5)/324 + (x+349)/5 = 0`
`-> (x+3)/327 + (x+3)/326 + (x+4)/325 + (x+5)/324 + (x+349)/5 + 4 - 4= 0`
`-> (x+3)/327 +1 + (x+3)/326 +1 + (x+4)/325 +1 + (x+5)/324 +1 + [(x+349)/5 - 4] = 0`
`-> (x+329)/327 + (x+329)/326 + (x+329)/325 + (x+329)/324 + (x+329)/5 = 0`
`-> (x+329).(1/327 + 1/326 + 1/325 + 1/324 + 1/5 ) = 0`
Do `(1/327 + 1/326 + 1/325 + 1/324 + 1/5) \ne 0`
`-> x+329 = 0`
`-> x = -329`
Vậy `x=-329`
`Go od luck!`