`#AkaShi`
Câu 5:
Đổi: `100ml=0,1 (l)`
`n_{NaOH}=C_{M NaOH}xxV(l)=0,1xx2,5=0,25 (mol)`
`⇒n_{NaOH}=10(g)`
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Đổi `200ml=0,2 (l)`
`⇒C_{ M CaCl_2}=n/(V(l))=(0,02)/(0,2)=0,1 (M)`
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`m_{dd sau pư}=144+6=150 (g)`
`⇒C%_{NaCl}=6/150xx1100%=4%`
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Câu 6:
a) PTHH: `Na + H_2O -> NaOH + H_2`
`n_{H_2}=V/(22,4)=(3,36)/(22,4)=0,15 (mol)`
`⇒n_{NaOH}=n_{H_2}=0,15 (mol)`
`⇒m_{NaOH}=0,15xx40=6 (g)`
b) `H_2 + CuO -> Cu + H_2O`
`n_{H_2}=0,15 (mol)`
`⇒n_{Cu}=n_{H_2}=0,15 (mol)`
`⇔m_{Cu}=nxxm=0,15xx64=9,6 (g)`
