`2)\frac{3}{4}-(x+\frac{1}{2})=\frac{4}{5}`
`<=>\frac{3}{4}-x-\frac{1}{2}=\frac{4}{5}`
`<=>\frac{1}{4}-x=\frac{4}{5}`
`<=>x=-\frac{11}{20}`
Vậy `x=-\frac{11}{20}`
`3)1\frac{2}{3}x-\frac{1}{4}=\frac{5}{6}`
`<=>\frac{5}{3}x=\frac{13}{12}`
`<=>x=\frac{13}{20}`
Vậy `x=\frac{13}{20}`
`4)|x-\frac{1}{2}|-\sqrt{\frac{1}{9}}=\sqrt{\frac{1}{4}}`
`<=>|x-\frac{1}{2}|-\frac{1}{3}=\frac{1}{2}`
`<=>|x-\frac{1}{2}|=\frac{5}{6}`
`=>x-\frac{1}{2}=±\frac{5}{6}`
`TH1:`
`x-\frac{1}{2}=\frac{5}{6}`
`<=>x=\frac{4}{3}`
`TH2:`
`x-\frac{1}{2}=-\frac{5}{6}`
`<=>x=-\frac{1}{3}`
Vậy `x=\frac{4}{3}` hoặc `x=-\frac{1}{3}`
