Đáp án:
$\displaystyle \begin{array}{{>{\displaystyle}l}} a.\ 36\\ b.\ 385\\ c.\ 2\\ d.\ \frac{1}{6}\\ f.17\\ g.13\\ h.\ 5\\ i.\ \frac{99}{20}\\ j.\frac{12-6\sqrt{3}}{5} \end{array}$
Giải thích các bước giải:
$\displaystyle \begin{array}{{>{\displaystyle}l}} a.\ 6\sqrt{2} .3.\sqrt{2} =36\\ b.\ \sqrt{5}\sqrt{11}\sqrt{7}\sqrt{11}\sqrt{5}\sqrt{7} =5.7.11=385\\ c.\ \left(\frac{3\sqrt{2}}{2} +\frac{\sqrt{2}}{2} -\sqrt{2}\right)\sqrt{2} =\sqrt{2}\sqrt{2} =2\\ d.\ \frac{2}{3} +\frac{3}{2} -2.\sqrt{\frac{2}{3} .\frac{3}{2}} =\frac{13}{6} -2=\frac{1}{6}\\ f.\left( 3\sqrt{2}\right)^{2} -1=9.2-1=17\\ g.\ 5^{2} -\left( 2\sqrt{3}\right)^{2} =25-4.3=13\\ h.\ \left( 7\sqrt{7} -5\sqrt{7} +3\sqrt{7}\right) :\sqrt{7} =5\sqrt{7} :\sqrt{7} =5\\ i.\ \frac{5\sqrt{0,5}}{\sqrt{0,5}} +\frac{\sqrt{6}}{5\sqrt{6}} -\frac{\sqrt{5}}{4\sqrt{5}} =5+\frac{1}{5} -\frac{1}{4} =\frac{99}{20}\\ j.\ \frac{\left( 1-\sqrt{3}\right)^{2} .3\sqrt{3}}{5\sqrt{3}} =\frac{12-6\sqrt{3}}{5} \end{array}$
