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meiko00
2 năm trước
cho a,b>0 a, $\frac{1}{1+a}$ + $\frac{1}{1+b}$ = √ $\frac{2}{1+√ab}$ khi nào b,$\frac{1}{1+a}$ + $\frac{1}{1+b}$ > √ $\frac{2}{1+√ab}$ khi nào c,$\frac{1}{1+a}$ + $\frac{1}{1+b}$ $\geq$ √ $\frac{2}{1+√ab}$ khi nào d,$\frac{1}{1+a}$ + $\frac{1}{1+b}$ $\leq$ √ $\frac{2}{1+√ab}$ khi nào
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