Giải thích các bước giải:
Bài 1:
a/. `3/4`.(x + 1) - `1/4`(x - 2) = `5/8`
⇔ `3/4`.x + `3/4` - `1/4`.x + `1/2` = `5/8`
⇔ `3/4`.x - `1/4`.x = `5/8` - `3/4` - `1/2`
⇔ (`3/4` - `1/4`).x = `5/8` - `6/8` - `4/8`
⇔ `2/4`.x = `(-5)/8`
⇔ `1/2`.x = `(-5)/8`
⇒ x = `(-5)/8` : `1/2`
⇒ x = `(-5)/8` . `2/1`
⇒ x = `(-5)/4`
b/. `2/3` - `1/3`(x -`3/2`) - `1/2`.(2x + 1) = 5
⇔ `2/3` - `1/3`(x -`3/2`) - `1/2`.(2x + 1) = 5
⇔ `1/3`(x -`3/2`) + `1/2`.(2x + 1) = `2/3` - 5
⇔ `1/3`x -`1/2` + x + `1/2` = `2/3` - `(15)/3`
⇔ (`1/3` + 1).x -`1/2` + `1/2` = `2/3` - `(15)/3`
⇔ (`1/3` + `3/3`).x = `(-13)/3`
⇔ `4/3`x = `(-13)/3`
⇔ x = `(-13)/3` : `4/3`
⇒ x = `(-13)/3` . `3/4`
⇒ x = `(-13)/4`
c/. (x - `3/5`).(3 - x) = 0
⇒ (x - `3/5`) = 0 hay (3 - x) = 0
⇒ x = `3/5` hay x = 3
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