Đáp án:
`text(P)=(-1)/64`
Giải thích các bước giải:
$\rm\#Japanese$
`text(P)= 3/2 + 5/4 + 9/8 + 17/16 + 33/32 + 65/64 - 7`
`=>text(P)=(1+1/2)+(1+1/4)+(1+1/8)+(1+1/16)+(1+1/32)+(1+1/64)-7`
`=>text(P)=6+(1/2+1/4+1/8+1/16+1/32+1/64)-7`
`=>text(P)=6+(underbrace(1/2+1/4+1/8+1/16+1/32+1/64)_(text(A)))-7`
`=>A=1/2+1/4+1/8+1/16+1/32+1/64`
`=>2A=2.(1/2+1/4+1/8+1/16+1/32+1/64)`
`=>2A=1+1/2+1/4+1/8+1/16+1/32`
`=>2A-A=(1+1/2+1/4+1/8+1/16+1/32)-(1/2+1/4+1/8+1/16+1/32+1/64)`
`=>A=1-1/64`
`=>text(P)=6+(1-1/64)-7`
`=>text(P)=6+1-1/64-7`
`=>text(P)=7-1/64-7`
`=>text(P)=(-1)/64`
Vậy `text(P)=(-1)/64`.
