a,
$(C_{17}H_{33}COO)_3C_3H_5+3NaOH\xrightarrow{{t^o}} 3C_{17}H_{33}COONa +C_3H_5(OH)_3$
$(C_{17}H_{35}COO)_3C_3H_5+3NaOH\xrightarrow{{t^o}} 3C_{17}H_{35}COONa+ C_3H_5(OH)_3$
$(C_{15}H_{31}COO)_3C_3H_5+3NaOH\xrightarrow{{t^o}} 3C_{15}H_{31}COONa+ C_3H_5(OH)_3$
b,
$m_{\text{triolein}}=1,05.40\%.10^3=420kg$
$\to n_{\text{triolein}}=\dfrac{420}{884}=\dfrac{105}{221}(kmol)$
$m_{\text{tristearin}}=1,05.35\%.10^3=367,5kg$
$\to n_{\text{tristearin}}=\dfrac{367,5}{890}=\dfrac{147}{356}(kmol)$
$m_{\text{tripanmitin}}=1,05.25\%.10^3=262,5kg$
$\to n_{\text{triolein}}=\dfrac{262,5}{806}=\dfrac{525}{1612}(kmol)$
$\to n_{C_3H_8O_3}=n_{CB}=1,214(kmol)$
$\to m_{C_3H_8O_3}=111,688 kg$
$n_{NaOH}=3n_{C_3H_8O_3}=3,642(kmol)$
BTKL:
$m_{\text{xà phòng}}=1050+3,642.40-111,688=1083,992kg$
