Cho tam giác ABC(AC > AB). Vẽ đường cao AH .Từ trung điểm I của cạnhAC ta vẽ ID vuông góc với cạnh huyền BC .Biết AB = 3cm , AC = 4cm . a/ Tính đọ dài cạnh BC . b/ Chöùng minh : IDC đồng dạng BHA c/ Cm hệ thức : BD2 – CD2 = AB2

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