Đáp án:
k, `((x + 3)^5)/( (x + 3)^2) = 64/27`
` (x + 3)^5 : (x + 3)^3 = 64/27`
` (x + 3)^(5 - 2) = 64/27`
` (x + 3)^3 = (4/3)^3`
` ⇒ x + 3 = 4/3`
` x = 4/3 - 3`
` x = -5/3`
Vậy `x = -5/3`
n, `(x + 1)/29 + (x + 3)/27 = (x - 3)/33 + (x - 7)/37`
`( (x + 1)/29 + 1) + ( (x + 3)/27 + 1) = ( (x - 3)/33 + 1) + ( (x - 7)/37 + 1)`
` (x + 30)/29 + (x + 30)/27 = (x + 30)/33 + (x + 30)/37`
` (x + 30)/29 + (x + 30)/27 - (x + 30)/33 - (x + 30)/37 = 0`
` (x + 30) . (1/29 + 1/27 - 1/33 - 1/37) = 0`
Mà `1/29 + 1/27 - 1/33 - 1/37 \ne 0`
`⇒ x + 30 = 0`
` x = 0 - 30`
` x = -30`
Vậy `x = -30`
