Đáp án:
Giải thích các bước giải:
$\left(2x\:-\:3\right)\left(3x\:+\:2\right)\:+\:\left(x\:+4\right)\:\left(4\:-\:6x\right)\:=-20$
$⇔6x^2-5x-6+\left(x+4\right)\left(4-6x\right)=-20$
$⇔6x^2-5x-6-6x^2-20x+16=-20$
$⇔-25x=-20-10=-30$
$⇔x=\dfrac{6}{5}$
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$\:\left(12x\:-\:5\right)\:\left(4x-1\right)\:+\:\left(3x-7\right)\left(1-16\:x\:\right)\:=\:81$
$⇔48x^2-32x+5+\left(3x-7\right)\left(1-16x\right)=81$
$⇔48x^2-32x+5-48x^2+115x-7=81$
$⇔83x-2=81$
$⇔83x=83$
$⇔x=1$