Đáp án:
ý a phải là -x+1 mới có thể giải ra kết quả
$\begin{array}{l}
a)27{\left( {x - 1} \right)^4} - x + 1 = 0\\
\Leftrightarrow \left( {x - 1} \right)\left( {27{{\left( {x - 1} \right)}^3} - 1} \right) = 0\\
\Leftrightarrow \left( {x - 1} \right).\left[ {{{\left( {3x - 3} \right)}^3} - 1} \right] = 0\\
\Leftrightarrow \left[ \begin{array}{l}
x - 1 = 0\\
3x - 3 = 1
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l}
x = 1\\
x = \frac{4}{3}
\end{array} \right.\\
Vậy\,x = 1;x = \frac{4}{3}\\
b){\left( {x - 2} \right)^2} - 4{\left( {2 - x} \right)^4} = 0\\
\Leftrightarrow {\left( {x - 2} \right)^2} - 4{\left( {x - 2} \right)^4} = 0\\
\Leftrightarrow {\left( {x - 2} \right)^2}\left( {1 - 4{{\left( {x - 2} \right)}^2}} \right) = 0\\
\Leftrightarrow \left[ \begin{array}{l}
x - 2 = 0\\
4{\left( {x - 2} \right)^2} = 1
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l}
x = 2\\
x - 2 = \frac{1}{2}\\
x - 2 = - \frac{1}{2}
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
x = 2\\
x = \frac{5}{2}\\
x = \frac{3}{2}
\end{array} \right.\\
Vậy\,x = 2;x = \frac{5}{2};x = \frac{3}{2}\\
c)4\left( {x - 3} \right) - {\left( {3 - x} \right)^3} = 0\\
\Leftrightarrow 4\left( {x - 3} \right) + {\left( {x - 3} \right)^3} = 0\\
\Leftrightarrow \left( {x - 3} \right)\left( {4 + {{\left( {x - 3} \right)}^2}} \right) = 0\\
\Leftrightarrow x - 3 = 0\\
\Leftrightarrow x = 3\\
Vậy\,x = 3
\end{array}$
