Đáp án + Giải thích: 
1) $\textit{(3x - 6)(7 - 10x) = 0}$
$\textit{Ta có:}$
$\textit{3x - 6 = 0 hoặc 7 - 10x = 0}$
$\textit{=> 3x = 6 hoặc 10x = 7}$
$\textit{=> x = 2 hoặc x = $\frac{7}{10}$}$
2) $\textit{(x - 6)(7 - x) = 0}$
$\textit{Ta có:}$
$\textit{x - 6 = 0 hoặc 7 - x = 0}$
$\textit{=> x = 6 hoặc x = 7}$ 
3) $\textit{(3x - 8)(15x + 5) = 0}$
$\textit{Ta có:}$
$\textit{3x - 8 = 0 hoặc 15x + 5 = 0}$
$\textit{=> 3x = 8 hoặc 15x = -5}$
$\textit{=> x $\frac{8}{3}$ hoặc x = $\frac{-5}{15}$ = $\frac{-1}{3}$}$
4) $\textit{(x - 2)(x + 7) = 0}$
$\textit{Ta có:}$
$\textit{x - 2 = 0 hoặc x + 7 = 0}$
$\textit{=> x = 2 hoặc x = -7}$
5) $\textit{(2x +1)(x - 4) = 0}$
$\textit{Ta có:}$
$\textit{2x + 1 = 0 hoặc x - 4 = 0}$
$\textit{=> 2x = -1 hoặc x = 4}$
$\textit{=> x = $\frac{-1}{2}$ hoặc x = 4}$
#ChucBanHocTot~

1) (3x - 6)( 7- 10x) =0

=>\(\left[ \begin{array}{l}3x-6=0\\7-10x=0\end{array} \right.\) 

=> \(\left[ \begin{array}{l}3x=6\\10x=7\end{array} \right.\) 

=> \(\left[ \begin{array}{l}x=2\\x=7/10\end{array} \right.\) 

2) (x-6)(7-x) = 0

=> \(\left[ \begin{array}{l}x-6=0\\7-x=0\end{array} \right.\) 

=> \(\left[ \begin{array}{l}x=6\\x=7\end{array} \right.\) 

3) (3x-8)(15x+5) = 0

=> \(\left[ \begin{array}{l}3x-8=0\\15x+5=0\end{array} \right.\) 

=>\(\left[ \begin{array}{l}3x=8\\15x=-5\end{array} \right.\) 

=> \(\left[ \begin{array}{l}x=8/3\\x=-1/3\end{array} \right.\) 

 4) (x-2)(x+7) = 0

=>\(\left[ \begin{array}{l}x-2=0\\x+7=0\end{array} \right.\) 

=>\(\left[ \begin{array}{l}x=2\\x=-7\end{array} \right.\) 

5) (2x+1)(x-4) = 0

=>\(\left[ \begin{array}{l}2x+1=0\\x-4=0\end{array} \right.\) 

=>\(\left[ \begin{array}{l}2x=-1\\x=4\end{array} \right.\) 

=> \(\left[ \begin{array}{l}x=-1/2\\x=4\end{array} \right.\) 

Xin hay nhất :)