Đáp án:
`A_{min}=-2` khi `x=-2`
Giải thích các bước giải:
`A=(x)/(x+3)(x\ne-3)`
`=(x+3-3)/(x+3)`
`=(x+3)/(x+3)-(3)/(x+3)`
`=1-(3)/(x+3)`
`A` min `<=>(3)/(x+3)` đạt GTLN
`<=>x+3` là số nguyên dương nhỏ nhất
`<=>x+3=1`
`<=>x=-2(tm:x∈ZZ;x\ne-3)`
Vậy `A_{min}=(-2)/(-2+3)=-2` khi `x=-2`
A=x/x+3 đk : (x#-3)
=x+3-3/x+3
=x+3/x+3-3/x+3
=1-3/x+3
=>3/x+3 đạt GTLN khi :
x+3=1
=>x=-2(tm)
Vậy GTNN của A khi x=-2
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