`***`Lời giải`***`
`|\frac{47}{2}-3x^2|=\frac{17}{2}`
`=>`\(\left[ \begin{array}{l}\dfrac{47}{2}-3x^2=\dfrac{17}{2}\\\dfrac{47}{2}-3x^2=-\dfrac{17}{2}\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}-3x^2=\dfrac{17}{2}-\dfrac{47}{2}\\-3x^2=-\dfrac{17}{2}-\dfrac{47}{2}\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}-3x^2=-15\\-3x^2=-32\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}3x^2=15\\3x^2=32\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x^2=5\\x^2=32/3\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}\left[ \begin{array}{l}x=\sqrt{5}\\x=-\sqrt{5}\end{array} \right.\\\left[ \begin{array}{l}x=\dfrac{4\sqrt{6} }{3}\\x=-\dfrac{4\sqrt{6} }{3}\end{array} \right.\end{array} \right.\)
