Đáp án:
$\begin{array}{l}
B1)\\
P\left( x \right) = - 4{x^3} + 3{x^2} - 2x + 5\\
= \left( { - 4{x^3} + 3x} \right) + \left( { - 2x + 5} \right)\\
= Q\left( x \right) + T\left( x \right)\\
Khi:\left\{ \begin{array}{l}
Q\left( x \right) = - 4{x^3} + 3x\\
T\left( x \right) = - 2x + 5
\end{array} \right.\\
B2)\\
Q\left( y \right) = - 7{y^6} + 6{y^4} - 3{y^3} + 5{y^2} + 1\\
= \left( { - 7{y^6} + 6{y^4}} \right) - \left( {3{y^3} - 5{y^2} - 1} \right)\\
= P\left( y \right) - T\left( y \right)\\
Khi:\left\{ \begin{array}{l}
P\left( y \right) = - 7{y^6} + 6{y^4}\\
T\left( y \right) = 3{y^3} - 5{y^2} - 1
\end{array} \right.
\end{array}$
