Đáp án:
a,x-$\frac{5}{6}$ =$\frac{-2}{3}$
=> x =$\frac{-2}{3}$ + $\frac{5}{6}$
=> x =$\frac{1}{6}$
b,- ( x+ $\frac{1}{6}$ ) = - ($\frac{3}{4}$ + $\frac{2}{5}$ )
=> - ( x+ $\frac{1}{6}$ ) = - ($\frac{23}{20}$)
=> x - $\frac{1}{6}$= $\frac{23}{20}$
=> x = $\frac{23}{20}$ + $\frac{1}{6}$
=> x = $\frac{79}{60}$
c,$\frac{x}{6}$ - $\frac{3}{2}$ = $\frac{-7}{15}$
=> $\frac{x}{6}$= $\frac{-7}{15}$ + $\frac{3}{2}$
=> $\frac{x}{6}$ = $\frac{31}{30}$
=> x = $\frac{31}{30}$ . 6
=> x = $\frac{31}{5}$
d, |x-5| = $\frac{-5}{3}$ + $\frac{1}{4}$
=> |x-5| = $\frac{-17}{12}$
vô lý vì |x-5| ko thể bằng $\frac{-17}{12}$
c, $\frac{x + 1}{8}$ =$\frac{1}{4}$
⇒ (x+1) . 4 = 8.1
⇒ 4x + 4 =8
⇒ 4x = 8 - 4
⇒ 4x = 4
⇒ x = 4 : 4
⇒x = 1
