Đáp án+Giải thích các bước giải:
f, F = ($\sqrt{\dfrac{3}{2}}$ - $\sqrt{\dfrac{2}{3}}$) : $\dfrac{1}{\sqrt{6}}$
= ($\dfrac{\sqrt{3}}{\sqrt{2}}$ - $\dfrac{\sqrt{2}}{\sqrt{3}}$) : $\dfrac{1}{\sqrt{6}}$
= $\dfrac{\sqrt{3}}{\sqrt{2}}$ : $\dfrac{1}{\sqrt{6}}$ - $\dfrac{\sqrt{2}}{\sqrt{3}}$ : $\dfrac{1}{\sqrt{6}}$
= $\dfrac{\sqrt{3}}{\sqrt{2}}$ . $\sqrt{6}$ - $\dfrac{\sqrt{2}}{\sqrt{3}}$ . $\sqrt{6}$
= $\sqrt{3}$ . $\sqrt{3}$ - $\sqrt{2}$ . $\sqrt{2}$
= 3 - 2
= 1
