$|2x-3|-|3x+2|=0\\↔|2x-3|=|3x+2|\\↔\left[\begin{array}{1}2x-3=3x+2\\2x-3=-(3x+2)\end{array}\right.\\↔\left[\begin{array}{1}2x-3x=2+3\\2x-3=-3x-2\end{array}\right.\\↔\left[\begin{array}{1}-x=5\\2x+3x=-2+3\end{array}\right.\\↔\left[\begin{array}{1}x=-5\\5x=1\end{array}\right.\\↔\left[\begin{array}{1}x=-5\\x=\dfrac{1}{5}\end{array}\right.$
Vậy $x∈\left\{-5;\dfrac{1}{5}\right\}$
