Đáp án+Giải thích các bước giải:
a,
$3x+\dfrac{5}{6}=x-4$
$⇒2x=\dfrac{-29}{6}$
$⇒x=\dfrac{-29}{12}$
Vậy $x=\dfrac{-29}{12}$
b,
$5x+\dfrac{1}{3}>-2x+\dfrac{-2}{3}$
$⇔7x>-1$
$⇔x>\dfrac{-1}{7}$
c,
$4x+\dfrac{4}{5}<\dfrac{3}{2}-x$
$⇔5x<\dfrac{7}{10}$
$⇔x<\dfrac{7}{50}$