Ta có:
`hat{C1} + hat{C2} = 180^o` (2 góc kề bù)
mà `hat{C1} - hat{C2} = 40^o`
`=> hat{C1} = (180^o + 40^o) : 2 = 110^o`
`=> hat{C2} = 180^o - 110^o = 70^o`
Vì `a `//` b`
`=> hat{C1} = hat{D2}; hat{C2} = hat{D1}` (2 góc sole trong)
`=> hat{D2} = 110^o; hat{D1} = 70^o`
Vậy `hat{D2} = 110^o; hat{D1} = 70^o`
(Chúc bạn học tốt)