$(38-x)^{}$ $(x+25)^{}$ =$0^{}$
⇔\(\left[ \begin{array}{l}38-x^{} = 0\\x+25^{}=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x^{} =38- 0\\x^{}=0-25\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x^{} = 38\\x^{}=-25\end{array} \right.\)
Vậy x=38 hoặc x=-25