`Tính`:
$a)(-2x^{3}+2x-5)$.$x^{2}$
$=-2x^{5}-2x^{3}-5x^{2}$
$b)(-2x^{3}).(5x-2y^{2}-1)$
$=-10x^{4}+4x^{3}y^{2}+2x^{3}$
`Bài 2`:
$a)4.(3x-1)-2.(5-3x)=-12$
$⇔12x-4-10+6x=-12$
$⇔12x+6x=4+10-12$
$⇔18x=2$
$⇔x=\frac{1}{9}$
Vậy $x=\frac{1}{9}$
$b)2x.(x-1)-3.(x^{2}-4x)+x.(x+2)=-3$
$⇔2x^{2}-2x-3x^{2}+12x+x^{2}+2x=-3$
$⇔12x=-3$
$⇔x=\frac{-1}{4} $
Vậy $x=\frac{-1}{4} $
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