Đáp án:
\(\left[ \begin{array}{l}x=-\dfrac{\pi}{3}-k2\pi\\x=\dfrac{4\pi}{9}+\dfrac{k2\pi}{3}\end{array} \right.\)`(kinZZ)`
Giải thích các bước giải:
`sin(x-pi/3)=sin2x`
`<=>`\(\left[ \begin{array}{l}x-\dfrac{\pi}{3}=2x+k2\pi\\x-\dfrac{\pi}{3}=\pi-2x+k2\pi\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}-x=\dfrac{\pi}{3}+k2\pi\\3x=\dfrac{4\pi}{3}+k2\pi\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=-\dfrac{\pi}{3}-k2\pi\\x=\dfrac{4\pi}{9}+\dfrac{k2\pi}{3}\end{array} \right.\)`(kinZZ)`
