Đáp án+Giải thích các bước giải:
`(2x+5)^2=9.(x-1)^2`
`⇔ (2x+5)^2 = (3x-3)^2`
`⇔ (2x+5)^2-(3x-3)^2 = 0`
`⇔ (2x+5-3x+3)(2x+5+3x-3) = 0`
`⇔ (8-x).(5x+2) = 0`
`⇔` \(\left[ \begin{array}{l}8-x=0\\5x+2=0\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=8\\\dfrac{-2}{5}\end{array} \right.\)
