Đáp án:
`m_C=1,9926.10^{-23}(g)`
`m_{Na}=3,81915.10^{-23}(g)`
`m_{Al}=4,48335.10^{-23}(g)`
Giải thích các bước giải:
`A_C=p+n=6+6=12(dvC)`
`=>m_C=12.1,6605.10^{-24}=1,9926.10^{-23}(g)`
`\text{}`
`A_{Na}=p+n=11+12=23(dvC)`
`=>m_{Na}=23.1,6605.10^{-24}=3,81915.10^{-23}(g)`
`\text{}`
`A_{Al}=p+n=13+14=27(dvC)`
`=>m_{Al}=27.1,6605.10^{-24}=4,48335.10^{-23}(g)`