Đáp án:
a)
`Fe + 2HCl -> FeCl_2 + H_2`
b)
`n_{H_2} = (4,994)/(22,4) = (2497)/(11200)` `mol`
`n_{Fe} = n_{H_2} = (2497)/(11200)` `mol`
`m_{Fe} = (2497)/(11200) . 56 = 12,485` `gam`
c)
`n_{HCl} = 2 . n_{H_2} = (2497)/(5600)` `mol`
`C_{M_(HCl)} = [(2497)/(5600)]/(0,05) = (2497)/(280)` `M`