$a)2|x^{}-3|-|4x-1|=0$
⇔ $2|x-3|^{}=|4x-1|$
⇔ \(\left[ \begin{array}{l}2(x-3)=4x-1\\2(x-3)=1-4x\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}2x-6=4x-1\\2x-6=1-4x\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}-2x=5\\6x=7\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=\dfrac{-5}{2}\\x=\dfrac{7}{6}\end{array} \right.\)
$b)|3x-5|^{}=|x+2|$
⇔ \(\left[ \begin{array}{l}x+2=3x-5\\x+2=5-3x\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}-2x=-7\\4x=3\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=\dfrac{7}{2}\\x=\dfrac{3}{4}\end{array} \right.\)
Chúc bạn học tốt !!!
