~ Bạn tham khảo ~
`a, (x+3)^2 - (x-4)(x+8) = 1`
`<=> x^2 + 6x + 9 - x^2 - 8x + 4x + 32 - 1 = 0`
`<=> 2x+40=0`
`<=> 2x=-40`
`<=> x=-20`
Vậy `x=-20`
`c, x^3 + 6x^2 + 12x + 35 = 0`
`<=> x^3 +x^2 + 7x + 5x^2 +5x+35=0`
`<=> x(x^2 + x + 7) + 5(x^2 + x + 7) = 0`
`<=> (x^2+x+7)(x+5)=0`
Mà `x^2 + x + 7`
`= x^2 + 2*1/2*x + 1/4 + 27/4`
`= (x+1/2)^2 + 27/4>=27/4>0`
`<=> x+5=0`
`<=> x=-5`
Vậy `x=-5`