CO2 + Ba(OH)2 --> BaCO3 + H2O
mol CO2 : 1,12 : 22,4 =0,05 mol
nồng độ mol Ba(OH)2 đã dùng là: 0,05:0,1=0,5M
khối lượng BaCO3 là:0,05x197=9,85 g
CHO MÌNH XIN 5 SAO NHÉ
Calli: Roey Nl: Không có gì ở đêy cả:))
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