`25 xx ( ( - 1 )/5 )^3 + 1/5 - 2 xx ( ( - 1 )/2 )^3 - 1/2`
`= 25 xx ( - 1 )/125 + 1/5 - 2 xx ( - 1 )/8 - 1/2`
`= ( - 1 )/5 + 1/5 - ( - 1 )/4 - 1/2`
`= ( ( - 1 )/5 + 1/5 ) - ( ( - 1 )/4 + 1/2 )`
`= 0 - 1/4`
`= ( - 1 )/4`
`25xx(-1/5)^3+1/5-2xx(-1/2)^3-1/2`
`=25xx[(-1)xx(1/5)^3]+1/5-2xx[(-1)xx(1/2)^3]-1/2`
`=(-25)xx1/125+1/5+2xx1/8-1/2`
`=(-1)/5+1/5+1/4-1/2`
`=-1/4`
`A=(\sqrt{x}-2)/(\sqrt{x}+2)` Tìm x để `\sqrt{A}>A`
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ìm từ có phần gạch chân phát âm khác so với các từ còn lại , ghi đáp án , giải thích , cần gấp nha mn , mình xin cảm ơn
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