`(2x^4 +x^3 - 5x^2 -3x - 3)/(x^2 - 3)`
`= (2x^4 + x^2 +x^3- 6x^2 - 3 - 3x)/(x^2 - 3)`
`= (x^2(2x^2 + x + 1) - 3(2x^2 + x +1))/(x^2 - 3)`
`= ((x^2 - 3)(2x^2 +x + 1))/(x^2 - 3)`
`= 2x^2 + x + 1`
Đáp án:
`=(2x²+x+1)`
Giải thích các bước giải:
`(2x^4 -5x^2 +x^3-3-3x):(x^2-3)`
`=2x^4+x²-6x²+x³-3-3x:(x^2-3)`
`=x²(2x²+x+1)-6x²-3-3x:(x^2-3)`
`=x²(2x²+x+1)-3(2x²+3x+1):(x^2-3)`
`=(x²-3)(2x²+x+1):(x^2-3)`
1,tìm x 2.3 mũ x=162 2 mũ x - 15=17 (7 mũx -11)mũ 3 = 5 mũ 2+200 x mũ 10=x
Câu 1 cả nha 😢😢😢😢😢😢😢❤❤❤❤❤❤❤
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